16. 碰撞的概率 [参考答案]
碰撞的概率 [参考答案]
\ 车辆 1|
\ |
\ |
车辆 2 \ | 左转 | 直行 | 右转
___________________________________
左转 |0.5|0.25|0.1
直行| 0.25 | 0.02 | 0.1
右转 | 0.1 | 0.1 | 0.01
Start Quiz:
def probability_of_collision(car_1, car_2):
"""
Calculate the probablity of a collision based on the car turns
Args:
car_1 (string): The turning direction of car_1
car_2 (string): The turning direction of car_2
Returns:
float: the probability of a collision
"""
probability = 0.0 # you should change this value based on the directions.
if car_1 == "L":
# Case Car1 L and Car2 L
if car_2 == "L":
probability = 0.5
# Case Car1 L and Car2 S
elif car_2 == "S":
probability = 0.25
# Case Car1 L and Car2 R (this is all other possible cases)
else:
probability = 0.1
elif car_1 == "S":
# Case Car1 S and Car2 L
if car_2 == "L":
probability = 0.25
# Case Car1 S and Car2 S
elif car_2 == "S":
probability = 0.02
# Case Car1 S and Car2 R (this is all other possible cases)
else:
probability = 0.1
else: # Car1 R
# Case Car1 R and Car2 L
if car_2 == "L":
probability = 0.1
# Case Car1 R and Car2 S
elif car_2 == "S":
probability = 0.1
# Case Car1 R and Car2 R (this is all other possible cases)
else:
probability = 0.01
return probability
def test():
num_correct = 0
p1 = probability_of_collision("L", "L")
if p1 == 0.5:
num_correct += 1
p2 = probability_of_collision("L", "R")
if p2 == 0.1:
num_correct += 1
p3 = probability_of_collision("L", "S")
if p3 == 0.25:
num_correct += 1
p4 = probability_of_collision("S", "R")
if p4 == 0.1:
num_correct += 1
print("You got", num_correct, "out of 4 correct")
test()